CSIR UGC NET Exam 2024: Dates, Eligibility, & Syllabus

CSIR UGC NET Exam 2024: Dates, Eligibility, & Syllabus

The National Testing Agency (NTA) will soon release the notification for the CSIR UGC NET Exam 2024 on its official website.

This examination is conducted to shortlist candidates for Junior Research Fellows and Lectureship/Assistant Professor posts in various Indian Colleges and Universities.

However, it is held twice a year, in June and December. Students who qualify for this exam will become lecturers in the college that falls under the faculty of Science and technology only.

Get here CSIR UGC NET exam dates, Syllabus, Eligibility Criteria, Exam Pattern, and more!

 

Highlights of CSIR NET

Particulars Details
Exam Name CSIR NET (Council of Scientific and Industrial Research National Eligibility Test)
Conducting Body National Testing Agency
Exam Frequency Twice a year
Exam purpose Select eligible candidates for Junior Research Fellowship and Lectureship/Assistant Professor in the colleges and universities.
Mode of Exam Online (Computer-based Test)
Website https://csirnet.nta.nic.in/

CSIR UGC NET Exam 2024 Dates

The NTA organizes the CSIR UGC NET Examination. To the CSIR UGC NET 2024 dates, check the schedule provided below.

Events Dates (June) Tentative Dates (December) Tentative
Notification Release February 2025 August 2024
Application form start date March 2025 September 2024
Last date to fill the form April 2025 September 2024
Last date fee payment April 2025 October 2024
Online correction window April 2025 October 2024
Admit card release date May 2025 November 2024
Exam Date June 2025 December 2024
Result declaration July 2025 January 2025

 

CSIR UGC NET Syllabus 2024

For the preparation of the examination, it is very important for the candidates to know about the syllabus. National Testing Agency releases the detailed syllabus of CSIR UGC NET. To learn the detailed examination syllabus, click on the link provided below.

 

CSIR UGC NET Exam Pattern 2024

The exam comprises five subjects: Mathematical Sciences, Social Sciences, Earth Sciences, Physical Sciences, and Chemical Sciences. Students can choose only one course at a time.

Chemical Science

No. of Parts Total Questions Marks per question
Part A 20 2
Part B 40 2
Part C 60 4

 

Earth Sciences

No. of Parts Total Questions Marks per question
Part A 20 2
Part B 50 2
Part C 80 4

 

Life Sciences

Parts Total no of questions Marks per question
Part A 20 2
Part B 50 2
Part C 75 4

 

Mathematical Sciences

No. of Parts Total Questions Marks per question
Part A 20 2
Part B 25 3
Part C 30 4.75

 

Physical Sciences

No. of Parts Total no of questions Marks per question
Part A 20 2
Part B 25 3.5
Part C 30 5

Eligibility Criteria

Before taking any steps, first check the eligibility norms. If one does not meet the eligibility norms, those will not be considered for the recruitment process.

Nationality: Candidates should have Indian Citizenship.

Age Limit

  • The age limit to apply for the CSIR UGC NET 2024 is 28 years.
  • For SC/ST/OBC/PWD candidates, there is an age relaxation of 5 years.
  • For women candidates: 3 years.

Education Qualification

The candidates must have an M.Sc. / Integrated BS-MS / BS-4 years / BE / B. Tech / B.Pharma / MBBS degree. Candidates belonging to the General/OBC and SC/ST/PWD categories should have obtained 55% and 50%, respectively.

CSIR UGC NET Exam 2024 Application Form

Candidates can fill out the form by following the below steps:

  • Visit https://csirnet.nta.nic.in/
  • To apply, click on the link available in public Notices
  • If you found the link to fill out the form, enter the personal and basic information.
  • View the research declaration and papers.
  • Press the Final Submit
  • Now, tap “Yes” to confirm registration.
  • Once done, the application number is generated.
  • Then, hit on the Complete Application.
  • Here, verify your email and phone number.
  • Enter the vital information like center, subject, or post applied for.
  • After that, enter the security key and press the

Important Note: Once you fill out the form by entering the required details, upload the scanned documents and pay the application fees. Once done, take a print out of the filled form and payment receipts for future references.

CSIR NET Application Fee

Students can pay the application fee online through various modes like debit/credit card, Net Banking, UPI, or Paytm gateway. The fees for various categories are listed below:

Category  Application Fee 
General INR 1000/-
OBC-NCL INR 500/-
SC/ST/ Physically Handicapped or Visually Handicapped INR 250/-

 

How to download CSIR NET Admit Card?

To download the admit card, students need to follow the steps below:

  1. Go to the CSIR official website.
  2. Enter information such as date of birth, application number, or password.
  3. Then, click the “Submit.”
  4. Once done, the admission form will appear on your screen.
  5. Here, you need to verify all the information.
  6. Tap the “Save” button to download the form.
  7. Finally, print a copy for future use.

Frequently Asked Questions-

What is the difference between UGC NET and CSIR NET?

The CSIR NET Exam is conducted to select candidates in Science, Engineering, and Technology, while the UGC NET exam selects students in Arts, Commerce, and Humanities.

What is CSIR NET exam eligibility?

Candidates need an M.Sc. or equivalent degree, an integrated BS-MS, BS-4 years, BE/B Tech, B. Pharma, or MBBS to apply for the CSIR NET exam.

What is the CSIR NET exam for?

The CSIR NET exam is conducted to test the capability of candidates for Junior Research Fellowship (JRF) and Lectureship (LS) /Assistant Professor in Indian universities and colleges.

What is the salary of CSIR NET?

The salary structure can vary, so for exact information, visit the official site of CSIR NET.

 

Final Remarks

I hope you have all the mandatory details regarding the CSIR UGC NET Exam 2024 without any difficulty or confusion. The article details exam patterns, important exam dates, eligibility criteria, etc. If you are still facing any issues or need more information, comment below!

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